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CGP EDU Academic Team
Published on: August 12, 2026
Solve the inequalities log 2 x ≥ logx + 2
Text Solution
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Sol. log x = t x > 0 log x ≥ 2 ∪ log x ≤ –1
t 2 ≥ t + 2 x ≥ 10 2 ∪ x ≤ 
t 2 – t – 2 ≥ 0 so x ∈ (0, 
] ∪ [100, ∞ )
(t – 2) (t + 1) ≥ 0
t ≥ 2 ∪ t ≤ – 1
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